The Weekly Challenge

HEADLINES

Welcome to the Week #325 of The Weekly Challenge.

Thank you, Yitzchak Scott-Thoennes, for sharing the blog post for the first time.

Thank you, HVukman, for sharing solution in J.

I noticed a big dip in guest contributions as compared to a week before i.e. from Week 323: 60 to Week 324: 38.

I hope it would take a jump this week, fingers crossed.

Happy Hacking!!

Last 5 weeks mainstream contribution stats. Thank you Team PWC for your support and encouragements.


`Week`	`Perl`	`Raku`	`Blog`
`320`	46	26	18
`321`	46	26	27
`322`	44	24	25
`323`	46	22	26
`324`	50	24	17

Last 5 weeks guest contribution stats. Thank you each and every guest contributors for your time and efforts.


`Week`	`Guests`	`Contributions`	`Languages`
`320`	14	62	23
`321`	13	61	23
`322`	13	56	19
`323`	12	60	21
`324`	12	38	15

TOP 10 Guest Languages

Do you see your favourite language in the Top #10? If not then why not contribute regularly and make it to the top.

 1. Python     (3410)
 2. Rust       (918)
 3. Ruby       (801)
 4. Haskell    (781)
 5. Lua        (726)
 6. C++        (621)
 7. C          (590)
 8. JavaScript (564)
 9. Go         (493)
10. BQN        (442)

Blogs with Creative Title

1. Two Dimensional XOR Not? by Adam Russell.

2. Exclusive or 2D by Arne Sommer.

3. Or Is It Reshaped? by Jorg Sommrey.

4. Reduce and Reduce, and Reduce! by Matthias Muth.

5. Total 2bular! by Packy Anderson.

6. Fun with arrays by Peter Campbell Smith.

7. The Total Array of Xor in 2-D by Roger Bell_West.

8. The total array by Simon Green.

GitHub Repository Stats

1. Commits: 43,833 (`+98`)

2. Pull Requests: 12,132 (`+36`)

3. Contributors: 260

4. Fork: 327

5. Stars: 191

With start of Week #268, we have a new sponsor Lance Wicks until the end of year 2025. Having said we are looking for more sponsors so that we can go back to weekly winner. If anyone interested please get in touch with us at perlweeklychallenge@yahoo.com. Thanks for your support in advance.

RECAP

Quick recap of The Weekly Challenge - 324 by Mohammad Sajid Anwar.

PERL REVIEW

If you missed any past reviews then please check out the collection.

RAKU REVIEW

If you missed any past reviews then please check out the collection.

CHART

Please take a look at the charts showing interesting data.

I would like to THANK every member of the team for their valuable suggestions. Please do share your experience with us.

NEW MEMBERS

Please find out How to contribute?, if you have any doubts.

Please try the excellent tool EZPWC created by respected member Saif Ahmed of Team PWC.

GUESTS

Please check out the guest contributions for the Week #324.

Please find past solutions by respected guests. Please share your creative solutions in other languages.

Task 1: Consecutive One

Submitted by: Mohammad Sajid Anwar

You are given a binary array containing only 0 or/and 1.

Write a script to find out the maximum consecutive 1 in the given array.

Example 1

Input: @binary = (0, 1, 1, 0, 1, 1, 1)
Output: 3

Example 2

Input: @binary = (0, 0, 0, 0)
Output: 0

Example 3

Input: @binary = (1, 0, 1, 0, 1, 1)
Output: 2

Task 2: Final Price

Submitted by: Mohammad Sajid Anwar

You are given an array of item prices.

Write a script to find out the final price of each items in the given array.

There is a special discount scheme going on. If there’s an item with a lower or equal price later in the list, you get a discount equal to that later price (the first one you find in order).

Example 1

Input: @prices = (8, 4, 6, 2, 3)
Output: (4, 2, 4, 2, 3)

Item 0:
The item price is 8.
The first time that has price <= current item price is 4.
Final price = 8 - 4 => 4

Item 1:
The item price is 4.
The first time that has price <= current item price is 2.
Final price = 4 - 2 => 2

Item 2:
The item price is 6.
The first time that has price <= current item price is 2.
Final price = 6 - 2 => 4

Item 3:
The item price is 2.
No item has price <= current item price, no discount.
Final price = 2

Item 4:
The item price is 3.
Since it is the last item, so no discount.
Final price = 3

Example 2

Input: @prices = (1, 2, 3, 4, 5)
Output: (1, 2, 3, 4, 5)

Example 3

Input: @prices = (7, 1, 1, 5)
Output: (6, 0, 1, 5)

Item 0:
The item price is 7.
The first time that has price <= current item price is 1.
Final price = 7 - 1 => 6

Item 1:
The item price is 1.
The first time that has price <= current item price is 1.
Final price = 1 - 1 => 0

Item 2:
The item price is 1.
No item has price <= current item price, so no discount.
Final price = 1

Item 3:
The item price is 5.
Since it is the last item, so no discount.
Final price = 5

Last date to submit the solution 23:59 (UK Time) Sunday 15th June 2025.